Question
Easy
If $5(3x + 4) тАУ 8(6x + 7) = 9x тАУ 8$, then what is the value of $(x^2 тАУ 2x + 1)$ ?
1
$\frac{2}{3}$
2
$\frac{4}{9}$
3
$\frac{5}{3}$
4
$\frac{25}{9}$
Question Details
Time to Solve: 12
Exam: CTET
Level/Paper: CTET_P2
Chapter: Algebra
Topic: Linear Equations in One Variables
Correct Answer
Option D
Explanation
To solve the given equation and determine the value of \((x^2 - 2x + 1)\), we need to first find the value of \(x\) from the equation: \[ 5(3x + 4) - 8(6x + 7) = 9x - 8 \] Let's simplify the equation step by step: 1. Distribute the numbers outside the parentheses: \[ 5 \times 3x + 5 \times 4 - 8 \times 6x - 8 \times 7тАжRead More
Similar Questions from REET Exam - Paper 1 - Year 2018
Question 1
Easy
Source :
Algebra
One of the factors of p$^3$x + p$^2$(x - y) тАУ p(y + z) - z is :
Chapter :
Algebra
Topic :
Factors
Question 2
Easy
Source :
Algebra
If (2x+5y)$^2$тИТ5(2x+5y) тАУ 14 = (2x+5y+p)(2x + 5y +q), then the value of (p+q) is :
Chapter :
Algebra
Topic :
Factors
Question 3
Easy
Source :
Algebra
The value of x which satisfies the equation 10(x + 6) + 8(x - 3) = 5(5x-4) also satisfies the equation
Chapter :
Algebra
Topic :
Linear Equations in One Variables
Question 4
Easy
Source :
Algebra
A taxi meter shows charges of тВ╣ 50 for the first two kilometres of journey and тВ╣16 for every subsequent kilometre travelled. Manju pays тВ╣258тАж
Chapter :
Algebra
Topic :
Linear Equations in One Variables